SOLUTION: Out of 7 women & 9 men a committee consisting of 3 women & 4 men is to be formed. I how many ways can this be done if (a)one particular man must included.

Algebra ->  Permutations -> SOLUTION: Out of 7 women & 9 men a committee consisting of 3 women & 4 men is to be formed. I how many ways can this be done if (a)one particular man must included.      Log On


   



Question 429254: Out of 7 women & 9 men a committee consisting of 3 women & 4 men is to be formed. I how many ways can this be done if (a)one particular man must included.
Answer by sudhanshu_kmr(1152) About Me  (Show Source):
You can put this solution on YOUR website!

Here one particular man must included, so we have to select only 3 women and 3 men out of 7 women and 8 men

no. of ways = 7C3 * 8C3
= 35 * 56

= 1960