SOLUTION: How many odd 6-digit pin numbers can be made from the digits 0-9?

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Question 418179: How many odd 6-digit pin numbers can be made from the digits 0-9?
Found 2 solutions by edjones, josmiceli:
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
10^6/2=500,000
.
Ed

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
There are 10 choices for the 1st digit (0-9)
There are 10 choices for the 2nd digit (0-9)
There are 10 choices for the 3rd digit (0-9)
There are 10 choices for the 4th digit (0-9)
There are 10 choices for the 5th digit (0-9)
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So far, there are
10%2A10%2A10%2A10%2A10+=+10%5E5 possible pin numbers
This must be multiplied by the number of
possible choices for the final digit which must be odd
It can't be 0 since the pin # would be even
It can be 1, 3, 5, 7, or 9
That is 5 choices, so there are
5*10^5 possible 6-digit odd pin #'s