SOLUTION: please help... I tried the 10*9*8*7*6*5*4*3*2*1 and that was not an option
a teacher has a set of 12 problems to use on a math exam. The teacher makes different versions of the
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-> SOLUTION: please help... I tried the 10*9*8*7*6*5*4*3*2*1 and that was not an option
a teacher has a set of 12 problems to use on a math exam. The teacher makes different versions of the
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Question 40456: please help... I tried the 10*9*8*7*6*5*4*3*2*1 and that was not an option
a teacher has a set of 12 problems to use on a math exam. The teacher makes different versions of the exam by putting 10 questions on each exam. How many differsnt exams can the teacher make? Answer by Nate(3500) (Show Source):
You can put this solution on YOUR website! You would use permutations:
P(12,10) = 12!/(2!) = 239,500,800
This is if she cares how the test questions are ordered.
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