SOLUTION: Sarah decided to try telemarketing. She calls people from 3pm to 9pm. Marley has a 15% chance of being called during this time. If Marley eats dinner from 6:6:30, how likely is it
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Question 395385: Sarah decided to try telemarketing. She calls people from 3pm to 9pm. Marley has a 15% chance of being called during this time. If Marley eats dinner from 6:6:30, how likely is it that she'll have a conversation with Sarah during this time? Answer by jrfrunner(365) (Show Source):
You can put this solution on YOUR website! let A=Marley is called during 3pm to 9pm
let B=Sarah calls someone during 6pm to 6:30pm
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Given P(A)=0.15
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P(B)=30/360 =1/12 since there are 30 minutes during the 6hours that he can be called.
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Need to know P(AnB) if we assume A & B are independent
then P(AnB)=P(A)*P(B)=0.15*1/12=0.0125
