SOLUTION: There are 2 girls and 7 boys in a math club. A team of four persons must be chosen for a tournament, and there must be at least 1 girl on the team. In how many ways can this be don

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Question 390478: There are 2 girls and 7 boys in a math club. A team of four persons must be chosen for a tournament, and there must be at least 1 girl on the team. In how many ways can this be done?
Found 2 solutions by stanbon, sudhanshu_kmr:
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
There are 2 girls and 7 boys in a math club. A team of four persons must be chosen for a tournament, and there must be at least 1 girl on the team. In how many ways can this be done?
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P(at least one girl on the team) = 1 - P(no girls on the team)
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= 1 - 7C4/9C4
= 1 - 0.278
= 0.722
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Cheers,
Stan H.

Answer by sudhanshu_kmr(1152) (Show Source):
You can put this solution on YOUR website!
2 girls, 7 boys , total 9 persons
No. of ways to choose 4 persons from 9 = 9C4

no. of ways to choose 4 persons from 7 boys = 7C4 ( no girls)

according to question, there must be at least 1 girl, so we will reduce number of ways in which no girls in team...

total no. of ways in which there must be at least 1 girl = 9C4 -7C4
= 126 - 35

=91

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