Question 360324: 12 balls are distributed at random among three boxes. How many ways are there that first box will contain 3 balls ?
Answer by sudhanshu_kmr(1152)   (Show Source):
You can put this solution on YOUR website!
First box will contain 3,it means other two will contain total 9 balls.
no. of ways to contain 9 balls in 2 boxes = (9+2-1)C(2-1) = 10C1 = 10
so, in 10 ways we can put 3 balls in first box.
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