SOLUTION: A board consists of 3 men and 4 women, How many different ways can they sit in a row where 2 women do not sit next to each other?

Algebra ->  Permutations -> SOLUTION: A board consists of 3 men and 4 women, How many different ways can they sit in a row where 2 women do not sit next to each other?      Log On


   



Question 359128: A board consists of 3 men and 4 women, How many different ways can they sit in a row where 2 women do not sit next to each other?
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
W M W M W M W IS is the only pattern allowed.
3!*4!=144 different ways.
.
Ed