SOLUTION: A hamburger place has 25 different toppings. You can have a hamburger with upto 5 different toppings. Assume no toppings are used more than once, how many different choices are av

Algebra ->  Permutations -> SOLUTION: A hamburger place has 25 different toppings. You can have a hamburger with upto 5 different toppings. Assume no toppings are used more than once, how many different choices are av      Log On


   



Question 352458: A hamburger place has 25 different toppings. You can have a hamburger with upto 5 different toppings. Assume no toppings are used more than once, how many different choices are available? I did this by 25x24x23x22x21= 6,375,600 Did I do this right?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
If the order of the toppings matters, then you are correct. However, I don't think the order matters (the book might say otherwise). If this is the case, then you need to divide by 5%21=120 to get 6375600%2F120=53130


So if order doesn't matter, then there are 53,130 different combinations.


If you need more help, email me at jim_thompson5910@hotmail.com

Also, feel free to check out my tutoring website

Jim