SOLUTION: In how many ways can a committee of 7 be formed if there are 10 dogs and 15 cats to choose from and the committee must consist of exactly 3 dogs and 4 cats?

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Question 352189: In how many ways can a committee of 7 be formed if there are 10 dogs and 15 cats to choose from and the committee must consist of exactly 3 dogs and 4 cats?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
Hi,
*Note: The probability of x successes in n trials is:
.
P = nCx* p%5Ex*q%5E%28n-x%29 where p and q are the probabilities of success and failure respectively.
.
nCx = n%21%2F%28x%21%28n-x%29%21%29
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Question states p(dog drawn) = 10/25 0r .4 and q (cat drawn) = .6
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Probability (3 dogs and 4 cats)
7C3 = +7%21%2F%283%21%2A4%21%29%21=+35+
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P((3 dogs and 4 cats) = 35%2A%28.4%29%5E3%2A%28.6%29%5E4 = .29
.