SOLUTION: In how many ways can a committee of 7 be formed if there are 10 dogs and 15 cats to choose from and the committee must consist of exactly 3 dogs and 4 cats?
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Question 352189: In how many ways can a committee of 7 be formed if there are 10 dogs and 15 cats to choose from and the committee must consist of exactly 3 dogs and 4 cats? Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website! Hi,
*Note: The probability of x successes in n trials is:
.
P = nCx* * where p and q are the probabilities of success and failure respectively.
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nCx =
.
Question states p(dog drawn) = 10/25 0r .4 and q (cat drawn) = .6
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Probability (3 dogs and 4 cats)
7C3 =
.
P((3 dogs and 4 cats) = = .29
.