SOLUTION: b) How many ways are there to distribute 20 district object into 10 distinct boxes with i) At least two empty box. ii) No empty box.

Algebra ->  Permutations -> SOLUTION: b) How many ways are there to distribute 20 district object into 10 distinct boxes with i) At least two empty box. ii) No empty box.       Log On


   



Question 350844: b) How many ways are there to distribute 20 district object into 10 distinct boxes with
i) At least two empty box.
ii) No empty box.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
b) How many ways are there to distribute 20 district object into 10 distinct boxes with
i) At least two empty box.
# of ways to select 2 distinct boxes: 10*9 = 90
---
# of ways to arrange 20 in the 8 remaining distinct boxes:
20P8 = 5079110900
------------------
Ans: 90*5079110900 = 4.5712x10^11
============================================
ii) No empty box.
20P10 = 20!/10! = 6.7044x10^11 ways
============================================
Cheers,
Stan H.