Question 349982: Joey and Ross along with 4 other best friends go to see a movie. They find a row of 6 seats, but Joey and Ross don’t want to sit next each other. How many different seating arrangements are possible if Joey and Ross don’t want to sit next each other?
Answer by sudhanshu_kmr(1152)   (Show Source):
You can put this solution on YOUR website! 6 seats and 6 persons, two of them should not sit together.
No. of ways to arrange 6 person at 6 place without any restriction = 6P6 = 6!
now, we will find how many ways these two friends can sit together .
assume both are single entity then total 5 person i.e 4 + (Joey + Ross)
no. of ways = 5p5 * 2! ( 2! for arrangement that they can make i.e JR,RJ)
= 5! * 2!
Now, this value can be subtracted from previous value where was no restriction
total no. of ways = 6! - 5! * 2
= 720 - 240
= 480
so, total 480 ways.
Sometime there may be typing mistake to solve a problem, so please ignore it.
Please understand the concept and try the problem yourself.
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