Question 335891: I know this is a combinatorial type of question, however, I am still baffled, your help on answering this question would be greatly appreciated.
In how many different sequences can we list 4 novels followed by 6 biographies if there are 8 novels and 10 biographies from which to choose?
Found 2 solutions by jrfrunner, scott8148:
Answer by jrfrunner(365)   (Show Source):
You can put this solution on YOUR website! if you are looking for "different orderings" its not combinations but permutations that you need to focus on.
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Number of different orderings of NNNNBBBBBB (where N=novel, B=biographies)
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since there are a total of 8 novels
the number orderings for the novels is 8*7*6*5 basically you first have 8 novels to choose from, then 7 novels after the first novel is chosen and so on.
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since there are a total of 10 biographies
the number orderings for the biographies is 10*9*8*7*6*5 basically you first have 10 biographies to choose from, then 9 biographies after the first biography is chosen and so on.
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Answer: (8*7*6*5)*(10*9*8*7*6*5)=254,016,000
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NOte this can be represented as (8P4)*(10P6) in permutation notation
Answer by scott8148(6628)  (Show Source):
You can put this solution on YOUR website! any of the novels' lists can be combined with any of the biographies' lists , so the answer is the product of the combinations
(8C4) * (10C6)
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