SOLUTION: a club with 10 members is to pick a president, vice president, treasurer, and secretary. If each office is to be held by one person and no person can hold 1 offices, in how many wa

Algebra ->  Permutations -> SOLUTION: a club with 10 members is to pick a president, vice president, treasurer, and secretary. If each office is to be held by one person and no person can hold 1 offices, in how many wa      Log On


   



Question 332800: a club with 10 members is to pick a president, vice president, treasurer, and secretary. If each office is to be held by one person and no person can hold 1 offices, in how many ways can those offices be filled?

Answer by jrfrunner(365) About Me  (Show Source):
You can put this solution on YOUR website!
a club with 10 members is to pick a president, vice president, treasurer, and secretary. If each office is to be held by one person and no person can hold 1 offices, in how many ways can those offices be filled?
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I think you must of meant "..no person can hold 'more than' 1 office..."
This is the case of the number of "different" ways to select 4 items out of 10.
where the order matters (who holds the president office matters) and no repetition is allowed. This is a permutation problem
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so there are 10 choices for president
then after that there are 9 choices for VP
then afte P and VP there are 8 choices for Treasurer
and finally after P, VP and T, there are 7 choices left for Secretary.
So the number of ways to fill those offices with 10 candidates is
10P4=10%21%2F%2810-4%29%21=+10%2A9%2A8%2A7=5040