SOLUTION: Five students and three teachers are to be seated in a row at the front of a school assembly. In how many different ways can this be done if there must be a teacher at each end of

Algebra ->  Permutations -> SOLUTION: Five students and three teachers are to be seated in a row at the front of a school assembly. In how many different ways can this be done if there must be a teacher at each end of       Log On


   



Question 326356: Five students and three teachers are to be seated in a row at the front of a school assembly. In how many different ways can this be done if there must be a teacher at each end of the row?
Answer by nyc_function(2741) About Me  (Show Source):
You can put this solution on YOUR website!
5P3 = 5!/(5 - 3)!
5P3 = 120/2!
5P3 = 120/2
5P3 = 60 ways