SOLUTION: if 16 dogs are entered into a dog show, in how many ways could you award first, second, and third place prize? This is what i thought but not sure?..16P3 16!/16-3!=16!/13!=3360

Algebra ->  Permutations -> SOLUTION: if 16 dogs are entered into a dog show, in how many ways could you award first, second, and third place prize? This is what i thought but not sure?..16P3 16!/16-3!=16!/13!=3360      Log On


   



Question 321032: if 16 dogs are entered into a dog show, in how many ways could you award first, second, and third place prize?
This is what i thought but not sure?..16P3 16!/16-3!=16!/13!=3360 is this right?

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
1st place is 1 of 16,
2nd place is 1 of 15,
3rd place is 1 of 14.
--> 16*15*14
= 3360