You can
put this solution on YOUR website! if ten digits 0 to 9 are arranged randomly with no repetition of digits how many different arrangements are possible?
Take an example, say:
0842971536
There are 10 ways to pick a digit to go where the 0 is.
That leaves 9 ways to pick a digit to go where the 8 is.
That leaves 8 ways to pick a digit to go where the 4 is.
That leaves 7 ways to pick a digit to go where the 2 is.
That leaves 6 ways to pick a digit to go where the 9 is.
That leaves 5 ways to pick a digit to go where the 7 is.
That leaves 4 ways to pick a digit to go where the 1 is.
That leaves 3 ways to pick a digit to go where the 5 is.
That leaves 2 ways to pick a digit to go where the 3 is.
That leaves 1 way to pick a digit to go where the 6 is.
Answer 10*9*8*7*6*5*4*3*2*1 = 10!= 3628800
Edwin
