Question 259864: If I have a rose, a carnation, a tulip, and a daisy; how many different ways are possible if I have a blue vase, a green vase, and a white vase?
Since a rose - carnation in a blue is the same as a carnation - rose in a blue, would this be 4!3!?
Thanks!
Answer by rfadrogane(214)   (Show Source):
You can put this solution on YOUR website! If I have a rose, a carnation, a tulip, and a daisy; how many different ways are possible if I have a blue vase, a green vase, and a white vase?
Since a rose - carnation in a blue is the same as a carnation - rose in a blue, would this be 4!3!?
Sol'n:
Your sol'n is correct:
N = 4!3! = 144 ways
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