SOLUTION: An urn contains 3 white balls and 5 red balls. Two balls are drawn at random. If the first is replaced before the second is drawn, what is the probability that the first ball is

Algebra ->  Permutations -> SOLUTION: An urn contains 3 white balls and 5 red balls. Two balls are drawn at random. If the first is replaced before the second is drawn, what is the probability that the first ball is       Log On


   

Question 257468: An urn contains 3 white balls and 5 red balls. Two balls are drawn at random. If the first is replaced before the second is drawn, what is the probability that the first ball is white and the second is red?
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
P(white then red) = 3/8*5/8 = 15/64.
Since we are replacing, the denominator stays the same.