Question 190473: a manufacturing company has to assign 6 digit lot numbers to its products using A-Z & 0-9, but the first dizit can not be a zero and the last two digits can not be alphabets(A-Z). so how many lot numbers can it produce?
Answer by solver91311(24713)   (Show Source):
You can put this solution on YOUR website!
There are 26 alphabetic characters A - Z and 10 numbers, 0 - 9.
Since you cannot use zero for the first digit, there are 26 + 9 = 35 ways to choose the first digit.
The second, third, and fourth digits can be anything, so there are 26 + 10 = 36 ways to choose each of those.
And the fifth and sixth position can only be alphabetic, so you only have 26 ways to choose each of the last two digits.
So for each of the 35 ways to choose the first digit, there are 36 ways to choose the second digit, so 35 X 36 = 1260 ways to choose the first two digits. For each of those ways there are 36 ways to choose the third digit...and so on, so:
You can operate a calculator as well as I can.
John
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