SOLUTION: If a ball is tossed into the air from height of 6 feet with a velocity of 32 feet per second, then its altitude at time t ( in seconds) can be described by the fuction A(t)=-16t^

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Question 174214: If a ball is tossed into the air from height of 6 feet with a velocity of 32 feet per second, then its altitude at time t ( in seconds) can be described by the fuction
A(t)=-16t^2+32t+6 Find the altitude of the ball at 2 seconds.
Now with this problem what I set this equation to zero?
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
You don't set anything equal to 0 in this case. You are given an equation that relates altitude to time. Then you are given a time and asked to find the altitude at that time
A%28t%29=-16t%5E2%2B32t%2B6 find A when t=2
A%282%29=-16%2A2%5E2%2B32%2A2%2B6
A%282%29+=+-64+%2B+64+%2B+6
A%282%29+=+6
The ball is 6 feet off the ground. It started at 6 feet (time =0), went up, peaked and is coming down. At 2 seconds, the ball is at the same height as time 0
graph%28400%2C400%2C+-1%2C4%2C+-1%2C25%2C+32x-16x%5E2%2B6%29