SOLUTION: if the perimeter of a rectangle is 20 feet and the diagonal is 2 sqrt13 feet, then what are the length and width?
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Question 173514: if the perimeter of a rectangle is 20 feet and the diagonal is 2 sqrt13 feet, then what are the length and width? Found 2 solutions by solver91311, Mathtut:Answer by solver91311(24713) (Show Source):
You can put this solution on YOUR website! P=2(L+W)...where L and W are length and width respectively
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we are given the diagonal the hypothenuse of a right triangle where L and W are the legs
: ...eq 1 ................eq 2
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lets re write eq 1 for L. 2L=20-2W---->L=(20-2W)/2-->L=10-W
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now lets plug in this L value into eq 2 and solve for W
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: multiplying out
: combining like terms on left side
: dividing by 2
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W can be either 4 or 6 but when
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W=4 then L=6 and when W=6 the L=4....
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