SOLUTION: how many3-digit numbers can be formed by using the digits 1 to 9 if no digit is repeated?
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Question 166200
:
how many3-digit numbers can be formed by using the digits 1 to 9 if no digit is repeated?
Found 2 solutions by
checkley77, edjones
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Answer by
checkley77(12844)
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9*8*7=504 possible 3 digit numbers without repeats.
Answer by
edjones(8007)
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9P3=9!/(9-3)!=9*8*7*6!/6!=504