SOLUTION: I have five possible days (Tues., Wed., Thurs.,Fri., and Sat.), which I need to group into threes without any repetition. How many possible combinations will result?
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Question 162823: I have five possible days (Tues., Wed., Thurs.,Fri., and Sat.), which I need to group into threes without any repetition. How many possible combinations will result? Answer by joecbaseball(37) (Show Source):
You can put this solution on YOUR website! You have five items (in this case days) from which you need to choose three without repetition. This is a combination problem.
The formula for this is 5C3 or "five choose three" and the formula is:
5! / (5-3)!3! which is (5x4x3x2x1) divided by (2x1)(3x2x1)
This gives you an answer of 10.
Good luck
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