SOLUTION: The Binomial Theorem...When (2a + b)^8 is expanded, what is the coefficient of the term a^3b^5? A little rusty but this is what I have done so far the binomial coefficient is 8

Algebra ->  Permutations -> SOLUTION: The Binomial Theorem...When (2a + b)^8 is expanded, what is the coefficient of the term a^3b^5? A little rusty but this is what I have done so far the binomial coefficient is 8       Log On


   



Question 146985: The Binomial Theorem...When (2a + b)^8 is expanded, what is the coefficient of the term a^3b^5? A little rusty but this is what I have done so far
the binomial coefficient is 8 over 5...evaluated would be 8!/3!*5!=56
then 56(2^3)(1^5)=448 I'm not sure that I did this correctly.
Thanks

Answer by scott8148(6628) About Me  (Show Source):