SOLUTION: A company has 11 software engineers and 7 civil engineers. In how many ways can they be seated in a row so that no two of the civil engineers will sit together?

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Question 1200684: A company has 11 software engineers and 7 civil engineers. In how many ways can they be seated in a row so that no two of the civil engineers will sit together?
Answer by ikleyn(52777) About Me  (Show Source):
You can put this solution on YOUR website!
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A company has 11 software engineers and 7 civil engineers. In how many ways
can they be seated in a row so that no two of the civil engineers will sit together?
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Under given conditions, each civil engineer either can be seated between two 
software engineers or at the extreme left or extreme right position from software engineers.


In all, there are 11+1 = 12 possible positions, where 7 civil engineers can be seated.


The number of such possible allowed placements is  

    C%5B12%5D%5E7 = %2812%2A11%2A10%2A9%2A8%29%2F%281%2A2%2A3%2A4%2A5%29 = 792.    ANSWER

Solved.

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For the purposes of this problem, the engineers are considered as undistinguishable objects
(although in reality they are distinct persons/individuals).

If you want to consider them as distinguishable persons, then the answer must be multiplied by 7!*11!.