SOLUTION: Consider the integers from 1,000 to 9,999 which have only odd digits.
a. How many of these have all different digits?
b. How many have odd digits with possible digit repetitions?
Algebra ->
Permutations
-> SOLUTION: Consider the integers from 1,000 to 9,999 which have only odd digits.
a. How many of these have all different digits?
b. How many have odd digits with possible digit repetitions?
Log On
Question 1199967: Consider the integers from 1,000 to 9,999 which have only odd digits.
a. How many of these have all different digits?
b. How many have odd digits with possible digit repetitions? Answer by ikleyn(52777) (Show Source):
You can put this solution on YOUR website! .
Consider the integers from 1,000 to 9,999 which have only odd digits.
a. How many of these have all different digits?
b. How many are there odd numbers with possible digit repetitions?
~~~~~~~~~~~~~~~~
So, there are 5 digits in use : 1, 3, 5, 7, and 9.
(a) There are 5*4*3*2 = 120 different numbers, as described. ANSWER
(b) There are 5*5*5*5 = = 625 different numbers, as described. ANSWER