SOLUTION: Did I solve the below word problem correctly using Permutation?
How many ways and 7 red flags, 1 white flag, 1 yellow flag and 2 blue flags be arranged on a pole?
7!/2! = 7 *
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-> SOLUTION: Did I solve the below word problem correctly using Permutation?
How many ways and 7 red flags, 1 white flag, 1 yellow flag and 2 blue flags be arranged on a pole?
7!/2! = 7 *
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Question 1192902: Did I solve the below word problem correctly using Permutation?
How many ways and 7 red flags, 1 white flag, 1 yellow flag and 2 blue flags be arranged on a pole?
7!/2! = 7 *6 / 2 = 21
Thank you Answer by greenestamps(13200) (Show Source):
The factorial in the numerator is the factorial of the total number of flags; the factorial(s) in the denominator are the factorials of the numbers of identical flags.
Total number of flags: 7+1+1+2 = 11
Repetitions: 7 red; 2 blue
