SOLUTION: How many 4-digit odd numbers can be formed from the digits 1, 3, 5, 6, 8, and 9 if repetition is allowed?

Algebra ->  Permutations -> SOLUTION: How many 4-digit odd numbers can be formed from the digits 1, 3, 5, 6, 8, and 9 if repetition is allowed?      Log On


   



Question 1192046: How many 4-digit odd numbers can be formed from the digits 1, 3, 5, 6, 8, and 9 if repetition is allowed?
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!

The cardinality of the set {1,3,5,6,8,9} is 6
6 choices for 1st digit *
6 choices for 2nd digit *
6 choices for 3rd digit *
4 choices for 4th digit = 6*6*6*4 = +highlight%28864%29+