SOLUTION: If you flip a coin 10 times, what is the probability that the first one is heads, the 2nd tails, the 3rd heads, the 4th is tails, and so on (keeps alternating for all 10 coins)?

Algebra ->  Permutations -> SOLUTION: If you flip a coin 10 times, what is the probability that the first one is heads, the 2nd tails, the 3rd heads, the 4th is tails, and so on (keeps alternating for all 10 coins)?       Log On


   

Question 1191632: If you flip a coin 10 times, what is the probability that the first one is heads, the 2nd tails, the 3rd heads, the 4th is tails, and so on (keeps alternating for all 10 coins)?
What I did was do 5/10•5/10•4/10•4/10... and so on until I got to ten coin flips. Doing this gave me a completely different answer from my answer key, please help me fix my mistakes! Thanks!
Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
.

The probability is  1%2F2  for each given separate individual flip, therefore, the probability 
to get this one combined pre-assigned case is


    P = %281%2F2%29%5E10%29 = 1%2F2%5E10 = 1%2F1024.    ANSWER

Solved, answered and explained.