SOLUTION: 7. Find the number of choices which a student has for doing 6 problems from a set of 11 problems. 8. 9.

Algebra ->  Permutations -> SOLUTION: 7. Find the number of choices which a student has for doing 6 problems from a set of 11 problems. 8. 9.       Log On


   

Question 1188842: 7. Find the number of choices which a student has for doing 6 problems from a set of 11
problems.
8.
9.
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
(1)   C%5B11%5D%5E6 = %2811%2A10%2A9%2A8%2A7%29%2F%281%2A2%2A3%2A4%2A5%29 = 462.    ANSWER

Solved.

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On Combinations,  see introductory lessons
    - Introduction to Combinations
    - PROOF of the formula on the number of Combinations
    - Problems on Combinations
    - OVERVIEW of lessons on Permutations and Combinations
in this site.

Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic  "Combinatorics: Combinations and permutations".


Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.


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