SOLUTION: A set of flash cards consists of 15 red, 12 blue, 10 black and 12 yellow cards. The cards in each colour are numbered from 1 through 15. (a) How many groups of 6 cards can be sel

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Question 1180849: A set of flash cards consists of 15 red, 12 blue, 10 black and 12 yellow cards. The cards in each colour are numbered from 1 through 15.
(a) How many groups of 6 cards can be selected from the entire set?
(b) How many groups of 6 can be selected from the red cards?
(c) How many groups of 24 cards can be selected from the entire set if there must be six of each colour?
Thank you in advance for any help:)

Answer by ikleyn(52778) About Me  (Show Source):
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A set of flash cards consists of 15 red, 12 blue, 10 black and 12 yellow cards. The cards in each colour are numbered from 1 through 15.
(a) How many groups of 6 cards can be selected from the entire set?
(b) How many groups of 6 can be selected from the red cards?
(c) How many groups of 24 cards can be selected from the entire set if there must be six of each colour?
Thank you in advance for any help:)
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The total number of the cards is 15 + 12 + 10 + 12 = 49.

The fact that the cards of each color are numbered MEANS that the cards are DISTINGUISHABLE, even if their color is the same.

The order of the cards in groups DOES NOT MATTER, so all three parts of the problem are on COMBINATIONS.


    (a)  The number of different groups of 6 cards is  C%5B49%5D%5E6 = 13983816.     ANSWER


    (b)  C%5B15%5D%5E6 = 5005.    ANSWER



    (c)  C%5B15%5D%5E6%2AC%5B12%5D%5E6%2AC%5B10%5D%5E6%2AC%5B12%5D%5E6 = 5005*924*210*924 = 897361264800.     ANSWER

All questions are answered. The problem is just solved, in full.


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This problem is on COMBINATIONS.

On Combinations,  see introductory lessons
    - Introduction to Combinations
    - PROOF of the formula on the number of Combinations
    - Problems on Combinations
    - Fundamental counting principle problems
    - OVERVIEW of lessons on Permutations and Combinations
in this site.

Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic  "Combinatorics: Combinations and permutations".


Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.