SOLUTION: There are 10 people in a meeting. In how many ways can you arrange your participants (including you) around a conference table if 4 people insist on sitting beside each other?

Algebra ->  Permutations -> SOLUTION: There are 10 people in a meeting. In how many ways can you arrange your participants (including you) around a conference table if 4 people insist on sitting beside each other?      Log On


   



Question 1178311: There are 10 people in a meeting. In how many ways can you arrange your participants (including you) around a conference table if 4 people insist on sitting beside each other?
Answer by ikleyn(52778) About Me  (Show Source):
You can put this solution on YOUR website!
.
There are 10 people in a meeting. In how many ways can you arrange your participants (including you)
around a highlight%28circular%29 conference table if 4 people insist on sitting highlight%28cross%28beside%29%29 next to each other?
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To see many similar  (and different)  problem solved,  look into the lesson
    - Persons sitting around a cicular table
in this site, and learn the subject from there.


Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this online textbook under the topic  "Combinatorics: Combinations and permutations".


Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.


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ANSWER.     6!*4! = 6*5*4*3*2*1*(4*3*2*1) = 17280 ways.