SOLUTION: There are 11 girls and 9 boys in Form 1A and 10 girls and 9 boys in Form 1B in a school. Eight students are to be selected from each Form to take part in an essay competition. Find
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-> SOLUTION: There are 11 girls and 9 boys in Form 1A and 10 girls and 9 boys in Form 1B in a school. Eight students are to be selected from each Form to take part in an essay competition. Find
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Question 1178038: There are 11 girls and 9 boys in Form 1A and 10 girls and 9 boys in Form 1B in a school. Eight students are to be selected from each Form to take part in an essay competition. Find, correct to three decimal places, the probability that equal number of girls and boys will be selected from:
(a) form 1A
(b) each form Answer by robertb(5830) (Show Source):
You can put this solution on YOUR website! (a) The probability of choosing 4 girls and 4 boys from Form 1A is . The probability of choosing 8 students from Form 1B is 1.
Therefore the probability of choosing 8 students from Form 1A under the specified condition is in 3 d.p.
(b) The probability of choosing 4 girls and 4 boys from Form 1B is .
Therefore the probability of choosing 8 students from each form under the specified condition is to 3 d.p.
