SOLUTION: In how many ways can you place 4 red balls,3 yellow balls,6 black balls,2 blue balls,and 1 orange ball in a row?

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Question 1177886: In how many ways can you place 4 red balls,3 yellow balls,6 black balls,2 blue balls,and 1 orange ball in a row?
Found 2 solutions by ikleyn, math_helper:
Answer by ikleyn(52777) About Me  (Show Source):
You can put this solution on YOUR website!
.

In  %284%2B3%2B6%2B2%2B1%29%21%2F%284%21%2A3%21%2A6%21%2A2%21%2A1%21%29 = 16%21%2F%284%21%2A3%21%2A6%21%2A2%21%2A1%21%29   different ways.


Complete calculations on your own.

Solved, instructed.

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To see other similar solved problems,  look into the lesson
    - Arranging elements of sets containing indistinguishable elements
in this site.

Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this online textbook under the topic  "Combinatorics: Combinations and permutations".


Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.



Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!

This is analogous to the number of distinguishable arrangements of the 16 letters {A,A,A,A,B,B,B,C,C,C,C,C,C,D,D,E}
16!/(4!*3!*6!*2!*1!) = 100900800 ways.