SOLUTION: Please help me to solve this Qeustion(1) Prove that nCr=n+1Cr-nCr-1 and Qeustion (2) Prove that nPr=(n-r+1) *nPr-1

Algebra ->  Permutations -> SOLUTION: Please help me to solve this Qeustion(1) Prove that nCr=n+1Cr-nCr-1 and Qeustion (2) Prove that nPr=(n-r+1) *nPr-1      Log On


   



Question 1175056: Please help me to solve this Qeustion(1) Prove that nCr=n+1Cr-nCr-1
and Qeustion (2) Prove that nPr=(n-r+1) *nPr-1

Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!

1) nCr = n!/((n-r)!r!) <<< this is what we need to show for the RHS
RHS: C(n+1,r) - C(n,r-1) where C(a,b) = "aCb"

=
Factor out n+1 from the first term, and multiply the 2nd term by r/r:
=
Notice (n+1-r)! ( = (n-(r-1))! ) is the same as (n+1-r)(n-r)!
=

Factor out n!/((n-r)!r!) and re-write:
=
= +%28n%21%2F%28%28n-r%29%21r%21%29%29+%2A++%28+%28%28n%2B1-r%29%2F%28n%2B1-r%29%29+%29+
= +%28n%21%2F%28%28n-r%29%21r%21%29%29++
= +nCr+


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(2) nPr = n!/(n-r)! = P(n,r) <<< P(x,y) notation used below
(n-r+1)*P(n,r-1)
= +%28n-r%2B1%29+n%21%2F%28n-%28r-1%29%29%21+
= +%28n-r%2B1%29+n%21%2F%28n-r%2B1%29%21+
= +cross%28%28n-r%2B1%29%29+n%21%2F%28cross%28%28n-r%2B1%29%29%28n-r%29%21%29+
= +nPr+