SOLUTION: A committee of 4 must be chosen from 4 lawyers 3 engineers. Find a. In how many ways can the committee be chosen b. In how many ways the committee can be equally represented by th

Algebra ->  Permutations -> SOLUTION: A committee of 4 must be chosen from 4 lawyers 3 engineers. Find a. In how many ways can the committee be chosen b. In how many ways the committee can be equally represented by th      Log On


   



Question 1174747: A committee of 4 must be chosen from 4 lawyers 3 engineers. Find a. In how many ways can the committee be chosen
b. In how many ways the committee can be equally represented by the 2 representative

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi
 7people:  4L and 3E
Committee of 4:
 2 of each:  (4C2)(3C2)= 6(3) = 18 ways

Wish You the Best in your Studies.