SOLUTION: There are _____ways that a student can answer the exam with 7 correct answers and 8 incorrect answers.

Algebra ->  Permutations -> SOLUTION: There are _____ways that a student can answer the exam with 7 correct answers and 8 incorrect answers.      Log On


   



Question 1173542: There are _____ways that a student can answer the exam with 7 correct answers and 8 incorrect answers.
Found 2 solutions by ewatrrr, ikleyn:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
There are _____ways that a student can answer the exam with 7 correct answers and 8 incorrect answers.
15 Questions: 7correct, 8 incorrect
Using Combinations (nCr) on Calculator:
Best not to over think it.
Yes, (15C7)= 6435 ways a student can answer the exam with 7 correct answers out of 15 questions. (others could have had no answer)
Wish You the Best in your Studies.

Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
.
There are _____ways that a student can answer the exam with 7 correct answers and 8 incorrect answers.
~~~~~~~~~~~~~


It is assumed (although does not formulated explicitly in the problem) that there are 8+7 = 15 questions, in all.



There are  C%5B15%5D%5E7  ways to select 7 questions from 15 questions to answer them correctly.


The rest questions will be automatically answered incorrectly.


Your  ANSWER  is  C%5B15%5D%5E7 = %2815%21%29%2F%287%21%2A8%21%29 = %2815%2A14%2A13%2A12%2A11%2A10%2A9%29%2F%281%2A2%2A3%2A4%2A5%2A6%2A7%29 = 6435 ways.

Solved.


/\/\/\/\/\/\/

Actually, the problem in the post is worded INCORRECTLY.

The correct wording is

    There are  15   questions  at an exam.

    In how many ways the student may answer 7 questions of them correctly ?


I observe it very often at this forum that the "local composers" formulate their problems INCORRECTLY,
because they do not know the subject professionally.