SOLUTION: Use the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9 to determine how many three digit numbers are possible when there are NO restrictions but numbers CANNOT be repeated.

Algebra ->  Permutations -> SOLUTION: Use the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9 to determine how many three digit numbers are possible when there are NO restrictions but numbers CANNOT be repeated.       Log On


   

Question 1169537: Use the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9 to determine how many three digit numbers are possible when there are NO restrictions but numbers CANNOT be repeated.

Answer by ikleyn(52776) About Me  (Show Source):
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Use the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9 to determine how many three digit numbers are possible
when there are NO restrictions but highlight%28cross%28numbers%29%29 digits CANNOT be repeated.
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Any of 9 non-zero digits in the 1-st, left-most position;


any of 9 remaining digits in the 2-nd position;


any of 8 remaining digits in the 3-rd position.



The total number is the product  9*9*8 = 648.     ANSWER

Solved.