SOLUTION: A group of 6 children are choosing colored pencils to draw a picture. Each child is allowed to select one color. The available colors are green, red, and blue. If the second child
Algebra ->
Permutations
-> SOLUTION: A group of 6 children are choosing colored pencils to draw a picture. Each child is allowed to select one color. The available colors are green, red, and blue. If the second child
Log On
Question 1168053: A group of 6 children are choosing colored pencils to draw a picture. Each child is allowed to select one color. The available colors are green, red, and blue. If the second child refuses to use red pencils and the third child refuses to use blue pencils, then how many ways are there for the children to choose pencils? Assume that there are 12 pencils available of each color, and different children are allowed to choose the same color. Answer by greenestamps(13198) (Show Source):
There are more than enough of each color pencil for every child to choose whatever color he chooses. So the total number of ways for the 6 children to choose pencils is the product of the numbers of colors each child can choose.
four of the six children can choose any of the 3 colors; two of them can only choose 2 of the 3.
