SOLUTION: How many three-digit numbers , in which no two digits are the same, can be made using the digits 0 1 3 5 8 if the numbers must be even and greater than 300

Algebra ->  Permutations -> SOLUTION: How many three-digit numbers , in which no two digits are the same, can be made using the digits 0 1 3 5 8 if the numbers must be even and greater than 300      Log On


   

Question 1153221: How many three-digit numbers , in which no two digits are the same, can be made using the digits 0 1 3 5 8 if the numbers must be even and greater than 300
Answer by greenestamps(13200) About Me  (Show Source):
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(1) The first digit has to be either 3, 5, or 8 (the 3-digit number has to be greater than 300):
3AB
5AB
8AB

(2) The last digit has to be 0 or 8 (the 3-digit number must be even); and no digit can be used twice:
3A0  3A8
5A0  5A8
8A0

For each of those combinations of first and last digits, the middle digit can be any of the three remaining digits:
310  350  380    308  318  358
510  530  580    508  518  538
810  830  850

ANSWER: 15 different 3-digit even numbers greater than 300 with no digits repeated