SOLUTION: Hello, Given a sey of digits 1 to 9. 9 digit numbers are to be formed from the set without repetition. Find the possible number of ways of getting the digits 1 and 2 precede the d

Algebra ->  Permutations -> SOLUTION: Hello, Given a sey of digits 1 to 9. 9 digit numbers are to be formed from the set without repetition. Find the possible number of ways of getting the digits 1 and 2 precede the d      Log On


   



Question 1151702: Hello,
Given a sey of digits 1 to 9. 9 digit numbers are to be formed from the set without repetition. Find the possible number of ways of getting the digits 1 and 2 precede the digits 3 and 4.

Answer by greenestamps(13198) About Me  (Show Source):
You can put this solution on YOUR website!


The number of 9-digit numbers using the digits 1-9 once each is 9!.

The probability that the 1 precedes the 3 is 1/2.
The probability that the 1 precedes the 4 is 1/2.
The probability that the 2 precedes the 3 is 1/2.
The probability that the 2 precedes the 4 is 1/2.

The number of 9-digit numbers using the digits 1-9 once each, in which the 1 and 2 precede the 3 and 4, is

%289%21%29%2A%281%2F2%29%5E4+=+9%21%2F16+=+22680