SOLUTION: A box has 6 blue socks and 4 white socks. Find the number of ways two socks can be drawn from the box where: (a) There are no restrictions. (b) They are different colors. (c) The

Algebra ->  Permutations -> SOLUTION: A box has 6 blue socks and 4 white socks. Find the number of ways two socks can be drawn from the box where: (a) There are no restrictions. (b) They are different colors. (c) The      Log On


   

Question 1150914: A box has 6 blue socks and 4 white socks. Find the number of ways two socks can be drawn from the box where:
(a) There are no restrictions. (b) They are different colors. (c) They are the same color.
Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
.

            In this problem, we consider and count only unordered pairs of socks. 


(a)   C%5B10%5D%5E2 = %2810%2A9%29%2F2 = 5*9 = 45  ways.      ANSWER



(b)   6*4 = 24  ways.                     ANSWER



(c)   It can be computed in 2 ways.


          1)  Having the numbers from (a) and (b), everybody can easily conclude 

              that the answer for (c)  is the difference  45 - 24 = 21  ways.



          2)  Another way to compute it is this :   C%5B6%5D%5E2 + C%5B4%5D%5E2 = 15 + 6 = 21.

              Surely, it gives the same answer.

Solved.


/\/\/\/\/\/\/\/\/

Just a reminder for visitors (!) 

     When I solve a problem for you, I expect to get your "THANKS" back.


     It is the simple and standard way to let me know that you are an educated person.


     Otherwise, I will think that I work for idiots.