Question 1150301: A major league baseball team selects 20 players to take part in each day's play.
In how many ways can the manager then select a nine-player batting lineup from the active roster for that day's play?
Answer by greenestamps(13198)   (Show Source):
You can put this solution on YOUR website!
P(20,9) = 20*19*18*17*16*15*14*13*12 = (big number...)
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To the student, who thinks my response is a "fraud"....
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There is not much more that can be added to an explanation. The manager clearly has 20 choices for the first player in the lineup, then 19 choices for the second, and so on until he has selected 9 players.
It is an elementary problem in permutations....
As for the answer, it is not our objective to work the problem to the end for you. Our objective is to help you learn HOW to work the problem and get the answer yourself.
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