SOLUTION: Ten people are to be seated at two circular tables. One table seats six people and the other seats four.
i) With these tables, how many different seating arrangements are there
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-> SOLUTION: Ten people are to be seated at two circular tables. One table seats six people and the other seats four.
i) With these tables, how many different seating arrangements are there
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Question 1142526: Ten people are to be seated at two circular tables. One table seats six people and the other seats four.
i) With these tables, how many different seating arrangements are there for the ten people?
ii) Assuming that the seating is random, what is the probability that a particular couple will be seated at the same table?
Thank you in advance! I'm not really great at perms and comms questions. If you could include an explanation in words, I would realy appreciate it :) Answer by ikleyn(52778) (Show Source):
(i) First, you can select 6 persons from 10 people by
ways = ways = 210 ways
to seat them around the first table. Then the team for the second table will be the rest (without further choice).
Second, you can arrange 6 people around the first circular table by = 5! ways = 120 ways
(using this standard well known formula).
Third, you can arrange 4 people around the second circular table by = 3! ways = 6 ways.
Finally, the answer to the problem's question is this product
210*120*6 = 151200 ways. ANSWER
