SOLUTION: Fred has 12 different books
Suppose that Fred first gives three books to Jill and then gives four of the remaining books to Jack how many different outcomes are possible?
Suppos
Algebra ->
Permutations
-> SOLUTION: Fred has 12 different books
Suppose that Fred first gives three books to Jill and then gives four of the remaining books to Jack how many different outcomes are possible?
Suppos
Log On
Question 1137240: Fred has 12 different books
Suppose that Fred first gives three books to Jill and then gives four of the remaining books to Jack how many different outcomes are possible?
Suppose that Fred first gives for books to Jack and then gives three of the remaining books to Jill how many different outcomes are possible?
Explain why the answers to Parts A and B are the same Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! the number of ways is 12C3*9C4
this is 12*11*10/6 multiplied by 9*8*7*6/24
The other way is 12*11*10*9/24 multiplied by 8*7*6/6
If one looks at both numerators and both denominators, it is clear that they are the same.
the answer is 27,720 ways.
