SOLUTION: There are nine female board members and twenty-one male board members.
How many ways are there to make a committee of twelve board members if exactly two must be female?
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-> SOLUTION: There are nine female board members and twenty-one male board members.
How many ways are there to make a committee of twelve board members if exactly two must be female?
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Question 1136801: There are nine female board members and twenty-one male board members.
How many ways are there to make a committee of twelve board members if exactly two must be female?
Determine the probability of selecting a committee of twelve board members where exactly two of the members were female. Write your answer as a decimal, rounded to the nearest thousandth. Answer by ikleyn(52777) (Show Source):
You can put this solution on YOUR website! .
There are nine female board members and twenty-one male board members.
(a) How many ways are there to make a committee of twelve board members if exactly two must be female?
(b) Determine the probability of selecting a committee of twelve board members where exactly two of the members were female.
Write your answer as a decimal, rounded to the nearest thousandth.
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(a) You can select 2 females of 9 females by = = 36 ways.
You can select 12-2 = 10 males of 21 males by = = ways = 352716 ways.
The answer to question (a) is the product of these numbers
. = 36 * 352716 = 12697776 ways.
(b) To answer question (b), you need to divide the answer to question (a) by the number of all combinations
of 21 items taken 12 at a time :
P = = .
I leave it to you to calculate the number and to complete this assignment. It is just pure mechanical work.
