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put this solution on YOUR website! An eight-oared boat is to be manned by a crew chosen from 11 men of whom 3 can
steer but cannot row and the rest cannot steer.In how many ways can the crew
be arranged if two of the men can only row on bow side?
The 11 crew-men consist of 3 steerers, 6 either-side-rowers, and 2 only-bow-side
rowers.
Since we must choose AND POSITION the men in a certain ORDER in the boat, we
must use PERMUTATIONS, for the ORDER they sit in MATTERS.
We can choose and position the steerer in 3P1 ways.
We can choose and position the 4 port-side rowers from the 6 either-side-
rowers in 6P4 ways.
We can position the 4 bow-side rowers from the remaining 6 rowers in 6P4 ways.
Answer: (3P1)(6P4)(6P4) = (3)(360)(360) = 388800 ways.
Edwin