SOLUTION: If 4 numbers from 1 to 1000 are chosen at random, one at a time, find the probability that they will be chosen in decreasing order. My work: does 1/24 include the numbers like 9

Algebra ->  Permutations -> SOLUTION: If 4 numbers from 1 to 1000 are chosen at random, one at a time, find the probability that they will be chosen in decreasing order. My work: does 1/24 include the numbers like 9      Log On


   



Question 1134955: If 4 numbers from 1 to 1000 are chosen at random, one at a time, find the probability that they will be chosen in decreasing order.
My work: does 1/24 include the numbers like 9998,7776,2221?

Found 2 solutions by MathLover1, ikleyn:
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

you got it right:1%2F24
does 1%2F24 include the numbers like 9998,7776,2221? no, you are given numbers from 1 to 1000

When 4+numbers are chosen, there are 4%21 possible permutations of them, influencing to their order.
Of this 4%21+=+1%2A2%2A3%2A4+=+24 permutations, only one provides the requested decreasing order.
Therefore, the probability under the problem's question is 1%2F24.

Answer by ikleyn(52778) About Me  (Show Source):
You can put this solution on YOUR website!
.

I solved this problem at least  TWO  TIMES  before,  and the number  1%2F24  came to you from my earlier posts.

See,  for example,  my response at the link

https://www.algebra.com/algebra/homework/Probability-and-statistics/Probability-and-statistics.faq.question.1134624.html

https://www.algebra.com/algebra/homework/Probability-and-statistics/Probability-and-statistics.faq.question.1134624.html


My answers were absolutely clear.


What is interesting,  the answer remains the same for any other domain instead of the segment  [1,1000].

For example,  the answer remains the same for the domain  [0,10000];  or for the domain  [-10,100001];

or for domain  (0,infinity)   (= all real positive numbers);  and even for the domain (-infinity,infinity)   (= all real numbers).

If it is what you want to ask,  then here you have my answer.