SOLUTION: how many ways can a 4 person subcommitte be selected from a committee of 12 people?

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Question 1131134: how many ways can a 4 person subcommitte be selected from a committee of 12 people?
Answer by ikleyn(52780) About Me  (Show Source):
You can put this solution on YOUR website!
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The same number of ways as the group of 4 items can be taken at a time from 12 items.


The order in the group is not important (the order does not matter) - so it is about combinations, and not about permutations.


Answer.  By  C%5B12%5D%5E4 = %2812%2A11%2A10%2A9%29%2F%281%2A2%2A3%2A4%29 = 495 ways.

Notice the difference between this problem and that of the link
https://www.algebra.com/algebra/homework/Permutations/Permutations.faq.question.1131135.html

https://www.algebra.com/algebra/homework/Permutations/Permutations.faq.question.1131135.html

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On Combinations and Permutations,  see introductory lessons
    - Introduction to Permutations
    - PROOF of the formula on the number of Permutations
    - Problems on Permutations

    - Introduction to Combinations
    - PROOF of the formula on the number of Combinations
    - Problems on Combinations

    - OVERVIEW of lessons on Permutations and Combinations
in this site.

Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic  "Combinatorics: Combinations and permutations".


Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.