SOLUTION: Three bolts and three nuts are put in a box. If two parts are chosen at random without replacement, find the probability that both are bolts

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Question 1126877: Three bolts and three nuts are put in a box. If two parts are chosen at random without replacement, find the probability that
both are bolts
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!

P(bolt chosen first) = 3/6 (this leaves 5 parts in the box)
P(bolt chosen 2nd) = 2/5 (2 out of the 5 remaining parts are bolts)
P(bolt chosen 1st and 2nd) = (3/6)*(2/5) = 6/30 = +highlight%28+1%2F5+%29+